If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2=1.2
We move all terms to the left:
x^2-(1.2)=0
We add all the numbers together, and all the variables
x^2-1.2=0
a = 1; b = 0; c = -1.2;
Δ = b2-4ac
Δ = 02-4·1·(-1.2)
Δ = 4.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.8}}{2*1}=\frac{0-\sqrt{4.8}}{2} =-\frac{\sqrt{}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.8}}{2*1}=\frac{0+\sqrt{4.8}}{2} =\frac{\sqrt{}}{2} $
| (4))x-9=1 | | 15x-6=2x-14 | | 9x=272-^2x | | X²+2x+3.25=0 | | 5-6x=26/36 | | 10=3x+36 | | 2(-3x+1)=18-4x | | 0=49+-9.8x | | 2t^2+3t=-7 | | 4+5(b-1)=34 | | -21×x=-126 | | 2×n+4=12 | | 2q2–7q+8=0 | | 1-5k=15 | | 3-x=11-2x | | 0.2(2x+3)=5-4x | | 2/3x=5x-13 | | 8x+1=5x+5(2x-11) | | 15-4(x+3)=12+5x | | 6–2p=12 | | 2+3x=8-3(x+2) | | 6–2x=12 | | 6–2b=12 | | 7-3(2-x)=4 | | 7-x=x-9 | | 1/2x+1=1/2 | | 3+2(3x-1)=5x+4 | | 3-5(2-x)=-12 | | 3(5-x)=4+2(x-2) | | 45/n=9/15 | | 11x-70=7 | | 2(x-5)=4+1/4x |